College Algebra CLEP Prep 2026 – 400 Free Practice Questions to Pass the Exam

Question: 1 / 410

When solving the equation (x – 2)^2 = 36, what is the value of x?

6

8

10

When solving this equation, we first need to isolate the variable x by taking the square root of both sides. Since the equation is already in the form of a perfect square, we can take the square root of both sides without needing to further simplify the equation.

√(x-2)^2=√36

|x-2|=6

Next, we need to solve for both the positive and negative values of x, so we need to set up two equations

x-2=6 and x-2=-6

Solving for x in each equation, we get:

x=8 and x=-4

However, the only value of x that satisfies the original equation is x=10. Therefore, the correct answer is C.

Option A is incorrect because it does not take into account the negative solution of x=-4.

Option B is incorrect because

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