College Algebra CLEP Prep 2025 – 400 Free Practice Questions to Pass the Exam

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If 48x^2y^4 = 24x^5y^2, what is the value of x?

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To solve this equation, we need to divide both sides by the common factors (48, x^2, y^2).

This will leave us with 1 = 2x^3y^2. To isolate x, we need to divide both sides by the coefficients of x, which is 2.

This will leave us with 1/2 = x^3y^2. To get x alone, we need to take the cube root on both sides. This will leave us with cube root of 1/2 = x^3.

To simplify the cube root of 1/2, we can rewrite 1/2 as 0.5. The cube root of 0.5 is approximately 0.7937. This means that x^3 is approximately 0.7937.

To solve for x, we need to

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