College Algebra CLEP Prep 2025 – 400 Free Practice Questions to Pass the Exam

Question: 1 / 410

What is the equation of the circle centered at (2,3) with a radius of 5?

(x-2)^2 + (y-3)^2 = 25

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In this question, the center of the circle is given as (2,3), so we substitute those values for h and k. The radius of the circle is given as 5, so we substitute that value for r. This gives us (x-2)^2 + (y-3)^2 = 25, which is option A.

Option B is incorrect because the radius is squared in the equation, so (x-2)^2 + (y-3)^2 cannot equal 5 for a circle with a radius of 5.

Option C is incorrect because the y-coordinate of the center is given as -3 instead of 3, so the equation becomes (x-

Get further explanation with Examzify DeepDiveBeta

(x-2)^2 + (y-3)^2 = 5

(x-2)^2 + (y+3)^2 = 25

(x+2)^2 + (y-3)^2 = 5

Next Question

Report this question

Download College Algebra CLEP Prep Practice Exam PDF Study Guide
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy